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0.16x-4x^2=0
a = -4; b = 0.16; c = 0;
Δ = b2-4ac
Δ = 0.162-4·(-4)·0
Δ = 0.0256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.16)-\sqrt{0.0256}}{2*-4}=\frac{-0.16-\sqrt{0.0256}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.16)+\sqrt{0.0256}}{2*-4}=\frac{-0.16+\sqrt{0.0256}}{-8} $
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